Algebraic Forms of Switching Functions (10)
- From the truth table
f '(A,B,C) = PM(0,2,4,6) and f(A,B,C) = PM(1,3,5,7)
- Since f(A,B,C) × f '(A,B,C) = 0,
(M0M2M4M6)(M1M3M5M7) = 0 or
- In general, (2.13)
- Another observation from the truth table:
f(A,B,C) = S m (0,2,4,6) = PM(1,3,5,7)
f '(A,B,C) = S m (1,3,5,7) = PM(0,2,4,6)